Show that for the implicit midpoint rule?

  • Thread starter Thread starter shehpar
  • Start date Start date
  • Tags Tags
    Implicit
shehpar
Messages
9
Reaction score
0
||e_i+1|| <= ||e_i||+h||f( (t_i+t_i+1)/2, y_i+y_i+1)/2)-f((t_i+t_i+1)/2, y(t_i+t_i+1)/2))||+O(h^3).

I need help about this question.if anybody able to guide me , I be thankful .
 
Physics news on Phys.org
shehpar said:
||e_i+1|| <= ||e_i||+h||f( (t_i+t_i+1)/2, y_i+y_i+1)/2)-f((t_i+t_i+1)/2, y(t_i+t_i+1)/2))||+O(h^3).

I need help about this question.if anybody able to guide me , I be thankful .
You need to provide more information than this. There is a template with three parts:

  1. The complete problem statement
  2. Relevant or useful equations
  3. What you have tried

You have provided an equation with no explanation of what the symbols mean, or any other information, so don't expect much help.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top