Show that function maps unit cirle onto a line

zezima1
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Homework Statement


Show that the function f(z) = z/(1-z) maps the unit circle to an infinite line.


Homework Equations


Polar form z = rexp(iθ)


The Attempt at a Solution


I've tried to see what happens, when we let f(z) = f(e) and then get:

f(e) = e/(1-e)

But I need some help on making this expression more illuminating. I want something for which I can take the real and imaginary part - what tricks can I use?
 
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zezima1 said:

Homework Statement


Show that the function f(z) = z/(1-z) maps the unit circle to an infinite line.

Homework Equations


Polar form z = rexp(iθ)


The Attempt at a Solution


I've tried to see what happens, when we let f(z) = f(e) and then get:

f(e) = e/(1-e)

But I need some help on making this expression more illuminating. I want something for which I can take the real and imaginary part - what tricks can I use?
Multiply the numerator & denominator of \displaystyle \frac{e^{i\theta}}{1-e^{i\theta}} by the complex conjugate of \displaystyle 1-e^{i\theta} which is \displaystyle 1-e^{-i\theta}\ .
 
Thanks, I'm still unsure how to do it though. Multiplying by the conjugate you get:

f(e) = (e-1)/(2-2cos(θ))

How do I show that this is the equation for a straight line?
 
zezima1 said:
Thanks, I'm still unsure how to do it though. Multiplying by the conjugate you get:

f(e) = (e-1)/(2-2cos(θ))

How do I show that this is the equation for a straight line?
Write (e-1) in terms of sin(θ) & cos(θ) .
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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