Show that two polynomials cannot span P2.

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Discussion Overview

The discussion revolves around the question of whether two polynomials can span the space of polynomials of degree less than or equal to 2, denoted as P2. Participants explore the dimensionality of polynomial spaces and the implications for spanning sets, as well as related concepts of linear independence and basis formation.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants assert that the dimension of P2 is 3, implying that two polynomials, which have a dimension of 2, cannot span P2.
  • One participant suggests a mathematical approach to demonstrate that a linear combination of two polynomials cannot cover all elements of P2.
  • Another participant raises a question about finding a basis for a set of vectors, indicating confusion about the representation of vectors in row or column form.
  • There is a discussion about the necessity of checking linear independence in different vector forms (row vs. column) when determining a basis.
  • Some participants clarify that the orientation of vectors (rows or columns) does not affect the outcome of the basis determination process.

Areas of Agreement / Disagreement

Participants generally agree on the dimensionality of P2 and the implications for spanning sets. However, there is some uncertainty regarding the process of finding a basis and the representation of vectors, indicating a lack of consensus on these procedural aspects.

Contextual Notes

The discussion includes assumptions about the definitions of polynomial spaces and linear independence, which may not be fully articulated. The relationship between the representation of vectors and their linear independence is also not resolved.

kingkong69
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Hi
I know the dimension is 3, two polynomials has dimension 2 only so it cannot span P2.
How would I go about showing it if I were to write it down mathematically?
Thanks
 
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kingkong69 said:
Hi
I know the dimension is 3, two polynomials has dimension 2 only so it cannot span P2.
How would I go about showing it if I were to write it down mathematically?
Thanks



Do you mean P2 is the space of all polynomials (over some field, say) of degree less than or equal to 2?

Well, take two such pol's ax^2+bx+c\,\,,\,\,a'x^2+b'x+c'\,\, , with a,b,c,a',b',c' elements of the field, and show that

\alpha(ax^2+bx+c)+\beta(a'x^2+b'x+c')\,\,,\,\, \alpha \,,\,\beta \,\, in the field, cannot possibly give all the elements of P_2...

DonAntonio
 
Hi
thanks i get u.

i have a question for you.
when I am given a set of vectors, i am asked to find a basis for it.

I solve it to Reduced row echolon form and get the basis.

But sometimes i have to write the vectors in columns, sometimes in rows for the matrice.
Sorry for being unclear

Do i need to check if the vectors are linearly independent in column space form? and then apply it in row space if they are dependent?

Thanks DonAntonio
 
kingkong69 said:
Hi
thanks i get u.

i have a question for you.
when I am given a set of vectors, i am asked to find a basis for it.


*** I'm guessing you actually mean that you have to find a basis for the space generated by that given set of vectors...right? ***


I solve it to Reduced row echolon form and get the basis.


*** Once again, I'm guessing you mean you write every polynomial as a row or column vector (it never matters, believe me) and then you

form a matrix with those rows (vectors) and then you reduce it...right? ***


But sometimes i have to write the vectors in columns, sometimes in rows for the matrice.
Sorry for being unclear



It doesn't matter rows or columns: it'sjust the same at the end.

DonAntonio
 

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