Show the length of vector z is the product of z1 and z2.

bfusco
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Homework Statement


consider a vector z defined by the equation z=z1z2, where z1=a+jb, and z2=c+jd (j=complex: same as 'i').
(a) show that the length of z is the product of the lengths of z1 and z2.
(b) show that the angle between z and the x-axis is the sum of the angles made by z1 and z2 separately.

P.S. this question is part of a personal study, so feel free to bring all information applicable without skipping steps, as to really solidify my understanding because i have to admit I've gotten to these 'upper level' math and physics classes and i feel as though i know nothing. lol

Thank you in advance!

The Attempt at a Solution


first off considering that this is 2 vectors being multiplied to get another vector I am assuming that this is the cross product. if that is the case than i would start by simply taking the determinant resulting in: ad-cb, but at i wouldn't know what to do past this point.
 
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bfusco said:

Homework Statement


consider a vector z defined by the equation z=z1z2, where z1=a+jb, and z2=c+jd (j=complex: same as 'i').
(a) show that the length of z is the product of the lengths of z1 and z2.
(b) show that the angle between z and the x-axis is the sum of the angles made by z1 and z2 separately.

P.S. this question is part of a personal study, so feel free to bring all information applicable without skipping steps, as to really solidify my understanding because i have to admit I've gotten to these 'upper level' math and physics classes and i feel as though i know nothing. lol

Thank you in advance!

The Attempt at a Solution


first off considering that this is 2 vectors being multiplied to get another vector I am assuming that this is the cross product. if that is the case than i would start by simply taking the determinant resulting in: ad-cb, but at i wouldn't know what to do past this point.

I don't believe that the cross product is called for here, and I also believe that the description of z as a vector is somewhat misleading. You are given that z1 and z2 are complex numbers, for which ordinary multiplication is defined.
 
It's really pretty easy if you express the complex numbers in polar form, if you gotten that far and want a shortcut.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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