Showing Range of Sequence in Metric Space is Not Always Closed

yifli
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Homework Statement


show that (the range of) a sequence of points in a metric space is in general not a closed set. Show that it may be a closed set.


2. The attempt at a solution
I don't know where to start.
For example, if we are given a sequence of real numbers and the distance between a and b is defined as |a-b|, it asks us to show that a sequence of real numbers is in general not a closed set?
 
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Pick your favorite convergent sequence. Is this a closed set?
 
Note the difference between the sets {1, 1/2, 1/3,..., 1/n,...} and {0, 1, 1/2, 1/3, 1/4, ..., 1/n, ...}
 
HallsofIvy said:
Note the difference between the sets {1, 1/2, 1/3,..., 1/n,...} and {0, 1, 1/2, 1/3, 1/4, ..., 1/n, ...}

thank you. I can see {1, 1/2, 1/3,...} is not closed, but {0,1,1/2,1/3,...} is.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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