Showing Tangency of y=(x2+x-2)3+3 at (1,3)

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Homework Statement


show that the tangent line to y=(x2+x-2)3+3 at (1,3) is also tangent to the curve at another point

Homework Equations


The Attempt at a Solution


dy/dx=3(x2+x-2)2(2x+1)
at 1
dy/dx = 0
y=mx+b
b=3
y=3
 
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hallowon said:

Homework Statement


show that the tangent line to y=(x2+x-2)3+3 at (1,3) is also tangent to the curve at another point

The Attempt at a Solution


dy/dx=3(x2+x-2)2(2x+1)
at 1
dy/dx = 0
y=mx+b
b=3
y=3

Then solving the equations y=3 and y=y=(x2+x-2)3+3 will give you two solutions, you know (1,3) is a solution, you just need to get the other solution.
 
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