Showing that there are particular sequences of functions that converge

jdinatale
Messages
153
Reaction score
0
problem_zps819d0945.png


answer_zpsc11573c9.png



That seems like a valid argument for showing that \phi_n converges to f, but I'm not sure how to show it's increasing. And as far \psi_n, converges, well I imagine that I'd use a similar argument, but I'm still not sure how to show it's decreasing.
 
Physics news on Phys.org
I agree it seems to be missing.

Since \phi_n is smaller than f, you can define
\tilde{\phi_n}(x) = \max_{j=1,...,n} \phi_k(x)
and this will still be within 1/n of f everywhere, and is increasing in n, and each \tilde{\phi_n} is a simple function. Exercise to prove all these properties.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top