Bashyboy
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Hello everyone,
I have the functions y_1 = \frac{c}{b} + d e^{-bx} andy_2 = \frac{c}{b} - d e^{-bx}, where c \in \mathbb{R}, and b,d \in \mathbb{R}^+.
What I would like to know is how to show that these two functions are symmetric about the line y = \frac{c}{d}.
What I thought was that if y_1 and y_2 are symmetric about the line y = \frac{c}{d}, then the distance between y_1 and y, and the distance between y_2 and y, will be the same. That is, d_1 = \sqrt{(y_1 - y)^2 + (x - x_0)^2} and d_2 = \sqrt{(y_2 - y)^2 + (x - x_0)^2}, where d_1 = d_2.
Is this a correct way of determining symmetry? Is it true in general? Are there any other ways in which I could prove symmetry?
I have the functions y_1 = \frac{c}{b} + d e^{-bx} andy_2 = \frac{c}{b} - d e^{-bx}, where c \in \mathbb{R}, and b,d \in \mathbb{R}^+.
What I would like to know is how to show that these two functions are symmetric about the line y = \frac{c}{d}.
What I thought was that if y_1 and y_2 are symmetric about the line y = \frac{c}{d}, then the distance between y_1 and y, and the distance between y_2 and y, will be the same. That is, d_1 = \sqrt{(y_1 - y)^2 + (x - x_0)^2} and d_2 = \sqrt{(y_2 - y)^2 + (x - x_0)^2}, where d_1 = d_2.
Is this a correct way of determining symmetry? Is it true in general? Are there any other ways in which I could prove symmetry?
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