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Signal Analysis - Invertibility

  1. Feb 7, 2007 #1
    I don't understand why my book is saying that this system is not invertible.

    y(t) = cos(x(t))


    Wouldn't, arccos{ y(t) } = x(t) and therefore be an inverse system?
  2. jcsd
  3. Feb 7, 2007 #2
    First check on what your book says the definition of invertible is.

    What about times T1 and T2, where T1 and T2 are different

    x(T1) = 0, x(T2)= 2PI

    y(T1) = 1 and y(T2)=1


    y(t)=1 what is the value of t?
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