Signal Analysis - Invertibility

  • Thread starter FrogPad
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  • #1
FrogPad
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I don't understand why my book is saying that this system is not invertible.

y(t) = cos(x(t))

?

Wouldn't, arccos{ y(t) } = x(t) and therefore be an inverse system?
 

Answers and Replies

  • #2
jing
123
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First check on what your book says the definition of invertible is.

What about times T1 and T2, where T1 and T2 are different

x(T1) = 0, x(T2)= 2PI

y(T1) = 1 and y(T2)=1

Suppose

y(t)=1 what is the value of t?
 

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