Simple Beat Frequency Problem

Homework Statement

Two identical piano wires have a fundamental frequency of 600 Hz when kept under the same tension.What fractional increase in the tension of wire will lead to the occurrence of 6.0 beat/sec when both wires oscillate simultaneously?

Homework Equations

fbeat=f2-f1

f=nv/2L

v=$$\sqrt{}T/\mu$$

The Attempt at a Solution

I used fbeat=f2-f1 to solve for f2 and ended up with 606Hz. I am really confused as to how to proceed. We were told that the answer should be 0.02 but I have know idea how to get that. Can you please give me a hint as to how to begin?

Thank you.

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You can also find the ratio of the tensions (that's what it means by fractional increase)

T=µv^2=µ*(2Lf/n)^2

so then look at T2/T1.

You can also find the ratio of the tensions (that's what it means by fractional increase)

T=µv^2=µ*(2Lf/n)^2

so then look at T2/T1.
I tried doing that and at first I ended up with 1.02. After staring at it a little I released that I needed to subtract 1 from my answer to get the fractional increase.

Thanks so much for your help!

Well, the ratio between them is 1.02 like you said, so T2 is 1.02 times greater than T1, or in percentages 102%. Fractional increase and percent increase is how much over 1 or 100%, respectively, the numbers are. If someone says a shirt increases in price by 250% then the shirt is really 350% of what it used to be, NewPrice=3.5*OldPrice. I personally don't see why people don't just say the shirt is 350% what it used to be, or has increased to 350% of the old price, but I'm not the one making the rules. :)

if its so simple then do it yourself

if its so simple then do it yourself