Simple boolean simplification - can i simplify it further?

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The discussion focuses on simplifying the Boolean function F(A,B,C,D) = Σ(2,3,5,7,11,13) using a two-level network design. The user attempts to simplify the function through a Karnaugh map and derives an expression involving C, A', D, and B. They explore factoring out C and confirm that a two-level circuit can be implemented using NAND gates in sum-of-products form. Ultimately, they arrive at the final expression F = C(A' + D xor B'). The user expresses gratitude after successfully figuring out the solution.
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Homework Statement



F(A,B,C,D) = (sum of) m (2,3,5,7,11,13)
Design a two level network to implement the above sum of products:

Homework Equations



F(A,B,C,D) = (sum of) m (2,3,5,7,11,13)

The Attempt at a Solution


Code:
K-map 
___Ab
CD|00..01..11..10 
00|
01|1...1...1
11|1...1...1
10|

My attempted solution:
F = CA' + CDB + CD'B'
F = CA' + C (DB + D'B')
F = CA' + C(D xor B)'
F = CA' + CD xor CB'

now can i factor out the C? This has to be two level so I'm thinking it'd take up two different blocks of logic gates.

Any help?
 
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What is a two level network may I ask?
 
the last line of it should be: F = C (A' + D xor B')

Since all have C in common. I'm probably wrong though.
 
OK. I found what the definition of a two-level circuit is: the implementation of a Boolean function with NAND gates is simplest if the function is in sum-of-products form. This form corresponds to a two-level circuit.

So, as a sum of products, I get that F = BC'D + A'BD + B'CD + A'B'C. You should be able to quickly draw the two-level circuit from it using NAND gates without any problems.
 
thanks a tonne i managed to figure it out a while back.
thanks
 
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