Simple Centripetal Force Question

AI Thread Summary
The discussion revolves around the confusion regarding the effects of tripling the radius on centripetal force and acceleration using different formulas. Two key formulas are mentioned: F_c = mv^2/r and F_c = m(4πr^2)/T^2. The answers vary based on whether speed or angular speed is held constant, leading to different conclusions about centripetal force. Clarification is sought on the context of the problem, as it significantly influences the outcome. Understanding the relationship between centripetal force, radius, and speed is essential for resolving the confusion.
chrisdapos
Messages
23
Reaction score
0
Hello, I know that there are two possible formulas to solve for radius. You can use (mv^2)/r ,or, (m4pir^2)/T^2. Now, the question is asking when the radius is trippled, the Centripital force is...?

Using the first equation, I come out with 1/3. Using the second equation, I come out with 9.

That confuses me enough, but when I looked back on a quiz we had (sometimes I get solutions from quizs), I found that my teacher asked when radius is tripled, centripital acceleration is...? The answer was 3. Can anyone provide some insight into what I am doing wrong and what equation i should use to get my answer. Thank you in advance!
 
Physics news on Phys.org
chrisdapos said:
Hello, I know that there are two possible formulas to solve for radius. You can use (mv^2)/r ,or, (m4pir^2)/T^2. Now, the question is asking when the radius is trippled, the Centripital force is...?
First off, there's another useful formula for centripetal force, which I show below. Realize that they are all equivalent; the only thing that changes are is variable of choice: linear speed, angular speed, period.

There's really not enough information given to give a sensible answer. It depends on what is being held constant. Can you give the exact question including any relevant context?

For example: If the problem stated something like "A car races on a circular track. If the speed stays the same, what happens to the centripetal force if the radius triples?" In that case, the relevant formula is the one containing v & r (F_c = m v^2 /r) and the answer is 1/3.

But what if it said "If the angular speed stays the same, what happens to the centripetal force if the radius triples?" In that case, the relevant formula is the one containing \omega & r (F_c = m \omega^2 r) and the answer is that the force triples.
 
Last edited:
The question reads exactly, if the radius were tripled, what would happen to the centripital force? The preceeding question is describe the relationship between Centripetal Force and: v, v^2, T and M. I don't think the preceeding question holds any context though. Thank you for your help!
 
Doc Al said:
First off, there's another useful formula for centripetal acceleration, which I show below. Realize that they are all equivalent; the only thing that changes are is variable of choice: linear speed, angular speed, period.

There's really not enough information given to give a sensible answer. It depends on what is being held constant. Can you give the exact question including any relevant context?

For example: If the problem stated something like "A car races on a circular track. If the speed stays the same, what happens to the centripetal force if the radius triples?" In that case, the relevant formula is the one containing v & r (a_c = m v^2 /r) and the answer is 1/3.

But what if it said "If the angular speed stays the same, what happens to the centripetal force if the radius triples?" In that case, the relevant formula is the one containing \omega & r (a_c = m \omega^2 r) and the answer is that the force triples.

isn't a_c = \frac{v^2}{r} and F = \frac{mv^2}{r}?
 
andrewchang said:
isn't a_c = \frac{v^2}{r} and F = \frac{mv^2}{r}?
Of course. Oops! :redface: I'll fix my post. (Thanks.)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top