Simple constant velocity question

AI Thread Summary
To average 60 km/h over a 90 km trip, the total travel time must be 1.5 hours. After averaging 40 km/h for the first 40 km, which takes 1 hour, 50 km remains to be covered in 0.5 hours. To achieve this, an average speed of 100 km/h is required for the remaining distance. The calculations confirm that this is the correct approach and answer.
cherryrocket
Messages
19
Reaction score
0
7. Q: "If you must average 60 km/h for a 90 km trip, and you only average 40 km/h for the first 40 km, what velocity must you average the rest of the way?"

A:

90 km 60km/h 1.5h
d v t

1st
40 km 40 km/s 1h
d v t

2nd
50 km ? 0.5h (1.5-1h = 0.5h)
d v t

v = d/t = 50km/0.5h = 100 km/h

Is this the right answer and is it the right way of solving it?
 
Physics news on Phys.org
Yes, looks right to me.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top