multivariable calculus II, I've been away from math for a long time and this is embarrassing.. anyways, ur answer = mine (plugged in few numbers to confirm), thanks all!mrkuo said:If I'm reading your problem correct, your answer seems more correct than his.
I've got [(sqrt x)*(3-x)]/[(2-x)^(3/2)] which should be the same answer in a more simplified format.
Now my question is: what kind of class are you taking where you would call this a "simple derivative"? :)
First off, this thread is almost 9 months old.lmnop said:I got 1/[(2-x)^2]
A simple derivative check is a method used to verify the accuracy of a mathematical derivative. It involves taking the derivative of a function using basic calculus rules and comparing it to the derivative calculated using numerical methods. If the two derivatives are close in value, it can be assumed that the derivative has been correctly calculated.
A simple derivative check is important because it allows us to verify the accuracy of our calculations. Small errors in a derivative can lead to significant errors in the final result, so it is crucial to ensure the accuracy of this calculation.
The steps involved in a simple derivative check are:
Common sources of error in a simple derivative check include choosing an inappropriate value for h, rounding errors in calculations, and errors in the original function used to calculate the derivative.
A simple derivative check should be used whenever there is a need to verify the accuracy of a derivative calculation. This can be in various fields including physics, engineering, economics, and more. It is also useful when writing computer programs that involve derivatives, as it can help catch any coding errors.