Simple differential equation

seto6
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Homework Statement


solve the following differential equation
(y')2 +x3y'-2x2y=0

Homework Equations



non

The Attempt at a Solution


i can't seem to find any way to solve it...
could someone give me a hint pls.!
 
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Some misleading title you have there: "simple differential equation..." :)
 
seto6 said:

Homework Statement


solve the following differential equation
(y')2 +x3y'-2x2y=0

Homework Equations



non

The Attempt at a Solution


i can't seem to find any way to solve it...
could someone give me a hint pls.!

You're sure that you have given us the correct differential equation, right?

If it were y'2 + xy' - 2x2y = 0, you could factor it into (y' + 2xy1/2)(y - xy1/2) = 0, and you could solve each one separately.

Or if you had y'2 + x3y' + 2x2y = 0, you could write this as y'2 + d/dx(x3y) = 0. I'm not sure what you could do with that, though.
 
I seem to find a solution of the form y = a xb, so try that. There's another of the form y = m xn + k too.
 
Last edited:
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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