- #1
James889
- 192
- 1
Hai,
I have the easiest problem but I am stuck at the last step, simplification.
[tex]\frac{cos3x+sin3x}{cos3x-sin3x}[/tex]
[tex]\begin{aligned}
F(x) = cos(3x)+sin(3x)\\
F'(x) = -3sin(3x)+3cos(3x) \\
G(x) = cos(3x)-sin(3x) \\
G'(x) = -3sin(3x)-3cos(3x)\end{aligned}
[/tex]
This gives [tex]\frac{(-3sin(3x)+3cos(3x))*(cos(3x)-sin(3x))+(cos(3x)+sin(3x))*(cos(3x)-sin(3x))}{(cos(3x)-sin(3x))^2}[/tex]
But how would i simplify this?
I have the easiest problem but I am stuck at the last step, simplification.
[tex]\frac{cos3x+sin3x}{cos3x-sin3x}[/tex]
[tex]\begin{aligned}
F(x) = cos(3x)+sin(3x)\\
F'(x) = -3sin(3x)+3cos(3x) \\
G(x) = cos(3x)-sin(3x) \\
G'(x) = -3sin(3x)-3cos(3x)\end{aligned}
[/tex]
This gives [tex]\frac{(-3sin(3x)+3cos(3x))*(cos(3x)-sin(3x))+(cos(3x)+sin(3x))*(cos(3x)-sin(3x))}{(cos(3x)-sin(3x))^2}[/tex]
But how would i simplify this?