Imagine nine vertical and parallel lines drawn side by side. They represent infinite planes of uniform voltage. The first line has 0 V. The 2nd line has 1 V. The 3rd has 2 V and so on, with the 9th line having 8 V. The distance between each line is 1 cm, which is 0.01 meter. There is an electron located on the vertical line with 2 V. This electron has a q = -1.6E-19 C and a mass = 9.11E-31 kg. What will be the acceleration of the electron assuming there are no other forces? MY SOLUTION d = 0.01 meter q = -1.6E-19 C mass = m =9.11e-31 kg E = delta V / delta d = 1 V / 0.01 m= 100 V/m F = Eq = ma F = (100 V/m)(-1.6E-19 C) = (9.11E-31 kg) a a = 1.76E13 m/s^2 Is this correct? My friend is getting something like 6.86E50 m/s^2 or 8.68E50 m/s^s.