Simple Harmonics and also some pressure

AI Thread Summary
A simple harmonic oscillator with an amplitude of 0.1m has equal kinetic and potential energies at a displacement of 0.07m, calculated using the formula x=A/√2. For the pressure-related problems, the force due to atmospheric pressure on one side of a door with an area of 2m² is approximately 405200N. When considering a pressure difference of 0.01 atm across the same door, the net force calculated is about 4052N, indicating that opening the door by hand would be challenging. The discussion highlights the relationship between kinetic and potential energy in oscillators, emphasizing the conservation of energy principle.
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Homework Statement


Hi

I have two problems i need to solve mainly 1, but i need to check if 2a and 2b is correct
here it is:

  1. A simple harmonics oscillator has an amplitude of 0,1m.At what displacement will its kinetic and potential energies be equal
  2. a) What is the force due to the atmosphere on one side of door of area 2m2?
    b) If the difference in pressure on the two sides of a closed door of area 2m2 is 0,01 atm, what is the net force on the door? Do you think you could open it by hand?

Homework Equations


in first problem i though of using x=A/√2 where A is the amplitude but i have no idea how to solve this in any way other.

In the two other problems i though of using p=F/A and then in last problem find the difference with F1-F2

The Attempt at a Solution



1) Though trying putting the x=A/√2 = 0,07 but I am not sure this is correct really since i just tried googling around for the answer and looking in the book.
Since our teacher give us this hint: v = dx/dt for x = Acoswt but idk how to use this.

2a) First i found F=P*A = 101300 Pa * 22 = 405200N

b) First i found the force F=P*A = 101300 Pa*0,99*2m2 = 401148 N

where the difference is F1-F2 = 405300-401148 = 4052N which would make it quite hard to try open the door
 
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