Simple Limits question regarding infinity

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Homework Statement




I am doing some squeeze theorem questions, and I always run into things that is something divided by ∞, or something divided by √∞

Why is it always zero?

like... -3/√∞ = 0 or -1/∞ = 0

why??




Homework Equations





The Attempt at a Solution

 
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Think about this for a moment. Infinity is not an actual number we can calculate, rather a concept we use to determine what happens over a never ending period of time.

For example consider :

lim_{x→∞} \frac{1}{x} = 0

So ask yourself for increasing values of x. Say x = 1, 2, 3, ..., n. f(x) is getting smaller and smaller and smaller the bigger and bigger the denominator gets. Notice the values of f(x) → 0 as x → ∞?

So conceptually, some quantity over something really really reeeeally big tends to zero as the bigger thing gets bigger.

Now what about the other case?

lim_{x→0^+} \frac{1}{x} = ∞

Same sort of argument here. Notice that for positive x = 1/2, 1/3, ..., 1/n, f(x) is getting bigger and bigger the smaller and smaller the denominator gets. So the values of f(x) → ∞ as x → 0.

Does this help?
 
nukeman said:

Homework Statement




I am doing some squeeze theorem questions, and I always run into things that is something divided by ∞, or something divided by √∞

Why is it always zero?

like... -3/√∞ = 0 or -1/∞ = 0

If you "run into things that is something divided by \infty", then you are doing the limits incorrectly- I suspect you are trying to "insert" \infty into the formula and you can't do that- "infinity" is not a number.

What you can say is that "limit as x (or n) goes to infinity" is shorthand for "as x (or n) gets larger and larger without bound:
So \lim_{n\to\infty} \frac{-1}{n} means we are looking at what happens as we make the denominator "larger, and larger, and larger, ...}. For example -1/1000000= -0.000001, -1/1000000000= -0.000000001, etc. Now, what do <b>you</b> think would happen if n got even larger and larger?<br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> why??<br /> <br /> <br /> <br /> <br /> <h2>Homework Equations</h2><br /> <br /> <br /> <br /> <h2>The Attempt at a Solution</h2> </div> </div> </blockquote>
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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