Simple Mechanics Problem -- Block connected to a wall by a rope

AI Thread Summary
The discussion revolves around a mechanics problem involving two blocks connected by a rope. The main issue is the calculation of tension (T) and the forces acting on both blocks, leading to confusion over negative acceleration for block B. Participants agree that a force slightly greater than 54N is required to initiate movement, and that increasing gravitational acceleration complicates the situation. There is consensus that the equations used, particularly regarding kinetic friction and normal force, may contain errors. The problem's setup raises suspicions about its correctness, as the dynamics described do not align with the expected outcomes.
domingoleung
Messages
7
Reaction score
1
Homework Statement
Block A (5 kg) is connected to the wall with a cord of tension T, and initially at rest on top of block B (10 kg) on a rough floor. If there is an applied force 54 N acting on block B, block B could move to the right while block A is still at rest due to the connecting cord. Assume the coefficient of kinetic friction between blocks A and B and between block B and the ground is μk = 0.3.

(i) Draw free body diagrams of blocks A and B.
(ii) Find the tension T of the cord and the acceleration of block B.
Relevant Equations
F = ma
asm1.png
(So this is the system given)

The following is my analysis:
(i)
WhatsApp Image 2020-03-18 at 00.15.27.jpeg

(ii)
WhatsApp Image 2020-03-18 at 00.15.43.jpeg

Well, my problem is - I got a negative acceleration and its quite impossible to have block B moving to the left. So I am wondering if there are any mistakes I've made.
 
Physics news on Phys.org
Can you write out the equations for all the forces on both blocks? Horizontal and vertical. In particular, can you check the calculation of ##T##. How did you get that?
 
PeroK said:
Can you write out the equations for all the forces on both blocks? Horizontal and vertical. In particular, can you check the calculation of ##T##. How did you get that?

Okay, ##T## is correct.

I think I agree with you. You need a force of slightly more than ##54N## to get this system moving.

Increasing ##g## to ##10 m/s^2## makes things worse, of course.

You can check once more, but unless we've made the same mistake, I think the problem might be wrong. It's a bit suspicious, as ##54N## is approximately the force needed.
 
Last edited:
Equation 2 is incorrect. ##f_{k1}=\mu_k F_{N1}## and ##F_{N1}## is given by equation 1.
 
kuruman said:
##f_{k1}=\mu_k F_{N1}## and ##F_{N1}## is given by equation 1.

That's true, but considering horizontal forces on block ##A## also gives:

##f_{k1} = T\cos \theta##
 
Ah yes. I forgot A is not accelerating. I agree that the 54 N force is not enough to provide an acceleration to the right. A negative acceleration could be compatible with the situation in which block B is already moving and then block A is dropped on it to slow it down, but that's not what the problem says.
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top