Simple Microscope Problem that I have been STUCK on

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To determine the object distance for a lens with a focal length of 50 mm that forms a virtual image magnified by a factor of 3, the correct approach involves using the magnification equation M = -s'/s and the lens formula 1/f = 1/s + 1/s'. The user initially misapplied the magnification formula, leading to confusion in calculating the object distance. By substituting the magnification into the lens equation, the correct object distance can be derived, which should yield 33 mm instead of the incorrect 40 mm. Clarification on the signs and proper application of the formulas is crucial for solving the problem accurately.
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Simple Microscope Problem that I have been STUCK on!

Homework Statement


How far from a lens of focal length 50 mm must the object be placed if it is to form a virtual image magnified in size by a factor of 3?


Homework Equations





The Attempt at a Solution


I thought I could us the equation...
M = s'-f/f to get s' and then use...
1/f = 1/s + 1/s' to get the object distance

but I am not coming up with the right answer??
 
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Can anyone help me on this? I still can't get the answer? I am suppose to get 33 mm and I m getting 40 mm
 
I don't understand this
M = s'-f/f

Shouldn't it be just M = -s'/s?
 
I don't know its in my book...
but I don't have s' or s??
I know F = 50 mm so...
50 = (1/s + 1/s')^-1
but I am still not getting it?
 
You are trying to find s, right? You were given M so you can solve for s' using the magnification equation and then substitute that into the lens equation which will let you solve for s.
 
Ok sooo...
-s' = ms
s' = -ms
1/ms + 1/s = 1/f
1/s * (1/m + 1/s) = 1/f
1/s = [(1/f) / (1/m + 1)]^-1 = 66.67? what am I doing wrong??
 
1/ms + 1/s = 1/f

This term should be negative since s' = -ms
 
Thank you soooooooooooooooooo much for your help!
 
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