- #1
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Can someone explain to me why for any operator A and functions f(x), g(x),
[tex](Af(x))^*g(x) = f^*(x)A^+g(x)[/tex]
Where "^+" denotes the hermitian conjugate of A.
I went to see the demonstrator about it and he couldn't explain/prove that result. Thx.
[tex](Af(x))^*g(x) = f^*(x)A^+g(x)[/tex]
Where "^+" denotes the hermitian conjugate of A.
I went to see the demonstrator about it and he couldn't explain/prove that result. Thx.