Archived Simple pendulum problem with only velocity and angle known

AI Thread Summary
The discussion revolves around calculating the oscillation time of a pendulum given an initial velocity of 10 cm/s and a maximum angle of deviation of 5 degrees. The user calculated the length of the string as 0.3 cm and the oscillation time as 0.35 seconds using the formula T = 2π√(L/g). However, the calculated length of 0.3 cm raises concerns about its feasibility, as it translates to only 3.5 mm, which seems unreasonable for a pendulum. Additional questions about the pendulum's energy distribution and the velocity at zero degrees suggest a deeper exploration of the problem's dynamics. Overall, the calculations prompt further scrutiny regarding the assumptions made in the problem.
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Homework Statement



We push a weight hanging on a long string in a horizontal direction so that the velocity at the beginning is v = 10 cm / s. What is the oscillating time of such a pendulum, if the string on which hangs deviates the most for θ = 5 º?

Homework Equations



T = 2pie[sqrt(L/g)]

The Attempt at a Solution



Calculating the length of the string:

v² = 2gL[1-cosθ] → L= v² / 2g[1-cosθ]
L= 0.3 cm

Calculating the oscillating time:

T = 2pie[sqrt(L/g)]
T= 0.35 s

Are my calculations correct?
Thank you for helping!
 
Last edited:
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You're told that the weight hangs on a "long" string, and it is given a speed of 10 cm/sec. Does it seem reasonable that L = 0.35 cm = 3.5 mm ?

From your equation for v2, what is v when θ = 0? Does that seem reasonable if the pendulum is oscillating?

What is the energy of the pendulum (assume a mass m for the weight on the end of the string)? How is it distributed between kinetic energy and potential energy? What condition determines the extent of the swing?
 
John, don't wait for a response from the OP; The last time the OP was logged in was back in 2010 and is thus unlikely to see your probing questions.

This problem is in the Open Practice Problems forum and as such you are free to go ahead and provide a complete solution.
 
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