Simple Region Question for a Double Integral Substitution

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SUMMARY

The discussion focuses on evaluating the double integral ∫∫(2x² - xy - y²) dx dy for the region R in the first quadrant, defined by the lines y = -2x + 4, y = -2x + 7, y = x - 2, and y = x + 1. The transformation used is x = (1/3)(u + v) and y = (1/3)(-2u + v), resulting in a Jacobian of 1/3. The transformed region is determined to be bounded by 4 ≤ v ≤ 7 and -1 ≤ u ≤ 2. It is confirmed that the transformed region does not need to be restricted to the first quadrant.

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Homework Statement


Evaluate the double integral integral ∫∫2x^2-xy-y^2 dxdy for the region R in the first quadrant bounded by the lines y=-2x+4, y=-2x+7, y=x-2, and y=x+1 using the transformation x=1/3(u+v), y=1/3(-2u+v).

Homework Equations


The Attempt at a Solution


I've obtained the Jacobian (it's 1/3) and I've plugged in the transformation equations into the line equations to get 4<=v<=7 and -1<=u<=2.

My question is pretty simple: if the region R is in the first quadrant, does the transformed region also need to be restricted to the first quadrant? As I'm typing this and thinking about it, It doesn't really make sense to restrict the transformed region to the first quadrant, but if someone could confirm that I would appreciate it.
 
Physics news on Phys.org
If the xy region is R, the integral over R transforms in uv space to the integral over whatever region R transforms to with the substitution.
 

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