eleventhxhour
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Simplify and state any restrictions on the variables:
$$\frac{2(x+1)}{3} ⋅ \frac{x-1}{6(x+1)} $$
This is what I did, which is wrong (according to the textbook).
$$\frac{2}{3} ⋅ \frac{x-1}{6}$$
$$\frac{2x-2}{18}$$
$$\frac{2(x-1)}{18}$$
Can someone tell me what I've done wrong? Also, how would you find the restrictions?
Thanks.
$$\frac{2(x+1)}{3} ⋅ \frac{x-1}{6(x+1)} $$
This is what I did, which is wrong (according to the textbook).
$$\frac{2}{3} ⋅ \frac{x-1}{6}$$
$$\frac{2x-2}{18}$$
$$\frac{2(x-1)}{18}$$
Can someone tell me what I've done wrong? Also, how would you find the restrictions?
Thanks.