MHB Simplify and state any restrictions on the variables.

AI Thread Summary
The discussion focuses on simplifying the expression $$\frac{2(x+1)}{3} ⋅ \frac{x-1}{6(x+1)}$$ and identifying restrictions on the variable. The initial simplification attempt incorrectly reduced the expression without fully simplifying the fraction $$\frac{2}{18}$$. A key mistake was not recognizing that the term $(x+1)$ in the denominator leads to division by zero when $x = -1$. The correct restrictions on the variable are that $x$ cannot equal -1, ensuring the expression remains defined. The final simplified expression should be correctly calculated to avoid errors.
eleventhxhour
Messages
73
Reaction score
0
Simplify and state any restrictions on the variables:

$$\frac{2(x+1)}{3} ⋅ \frac{x-1}{6(x+1)} $$

This is what I did, which is wrong (according to the textbook).

$$\frac{2}{3} ⋅ \frac{x-1}{6}$$

$$\frac{2x-2}{18}$$

$$\frac{2(x-1)}{18}$$

Can someone tell me what I've done wrong? Also, how would you find the restrictions?

Thanks.
 
Mathematics news on Phys.org
It appears that you simply did not simplify fully...what is:

$$\frac{2}{18}$$

fully reduced?

In the original expression, what value of $x$ will cause division by zero?
 
Ohh, I see. That was a simple mistake.
Thanks!
And the restriction would be -1.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Replies
5
Views
2K
Replies
4
Views
1K
Replies
9
Views
2K
Replies
23
Views
2K
Back
Top