Simplify Equation: How to Solve for C?

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The discussion revolves around simplifying the equation 1/A = B(1/C - 1/D) to solve for C. Initially, the user reaches the equation 1 = C(1/AB + 1/D) but struggles to isolate C. After confirming the equation, the user successfully derives C = 1/(1/AB + 1/D) but seeks further simplification. Guidance is provided on using common denominators to simplify the expression, leading to the final result of C = ABD/(D + AB). The user confirms the correctness of this final equation.
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i'm having trouble simplifying an equation.
Basically it's in the form of 1/A=B(1/C-1/D)
Now what i can't to do is solve for C.

I get to 1 = C(1/AB + 1/D) but do not know where to go from there.

Any help would be much appreciated, thanks.
 
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First of all we need to verify your starting equation, is it:

\frac 1 A = B (\frac 1 C - \frac 1 D )
 
Skullmonkee said:
I get to 1 = C(1/AB + 1/D) but do not know where to go from there.

Yes you're nearly there.

Let \frac{1}{AB}+\frac{1}{D}=x so now we have 1=Cx

What would you do at this point to solve (isolate the variable) for C?
 
Yes intergral, that is the starting equation.

Thanks Mentallic but i have a question.

If i isolate the variable, C won't i get something like this:

Let x be as you have stated. C = 1/x

Now wouldn't the equation be C = 1/(1/AB + 1/D). Is this as far as i can go?
 
Ok good, you've solved for C. However, it can be simplified further.

Are you aware of the results:

\frac{a}{b}+\frac{x}{y}=\frac{ay+bx}{by} by finding the lowest common denominator?

and

\frac{1}{\left(\frac{a}{b}\right)}=\frac{b}{a} ?

Applying these two ideas, you'll be able to simplify the answer :smile:
 
Thankyou.

I used the equations that you gave me (forgotten high school maths) and was able to get:

C = ABD/D+AB

I hope this is correct?
 
That's correct all right!
 
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