Simplifying a cosine + cosine with conjugate denominators

AI Thread Summary
The discussion centers on simplifying the expression -\frac{1}{2}[cos(\frac{\pi+\pi n}{\pi+\pi n}) + cos(\frac{\pi-\pi n}{\pi-\pi n})]. Participants note that the fractions simplify to 1 for most values of n, raising questions about any potential restrictions on n, which are not stated in the problem. There is also speculation that the expression may originate from a miscalculated Fourier Series problem. The use of the trigonometric identity cos(u)cos(v) = \frac{1}{2} cos(u+v)+cos(u-v) is mentioned as a potential method for simplification. Overall, the conversation highlights confusion over the expression's origin and the simplification process.
luckyduck
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Homework Statement



-\frac{1}{2}[cos(\frac{\pi+\pi n}{\pi+\pi n}) + cos(\frac{\pi-\pi n}{\pi-\pi n})]

Homework Equations



cos(u)cos(v) = \frac{1}{2} cos(u+v)+cos(u-v)

The Attempt at a Solution


I am attempting to use the above trig function to simplify the first function, but I can't seem to do it properly. Is there another function for when the contents of the cos are equal to its denominator?

Thanks in advance for all your help!
 
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luckyduck said:

Homework Statement



-\frac{1}{2}[cos(\frac{\pi+\pi n}{\pi+\pi n}) + cos(\frac{\pi-\pi n}{\pi-\pi n})]

Homework Equations



cos(u)cos(v) = \frac{1}{2} cos(u+v)+cos(u-v)

The Attempt at a Solution


I am attempting to use the above trig function to simplify the first function, but I can't seem to do it properly. Is there another function for when the contents of the cos are equal to its denominator?

Thanks in advance for all your help!
Don't the fractions simplify to 1 for nearly all values of n? BTW, are there any restrictions on n?
 
I keep getting weird numbers. Problem doesn't state any restrictions!
 
luckyduck said:

Homework Statement



-\frac{1}{2}[cos(\frac{\pi+\pi n}{\pi+\pi n}) + cos(\frac{\pi-\pi n}{\pi-\pi n})]

Mark44 said:
What are you getting?

More to the point, where did that expression come from? I'm guessing almost certainly from an incorrectly worked Fourier Series problem.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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