razored Messages 173 Reaction score 0 Thread starter Apr 29, 2009 #1 [tex]\Sigma_{n=1}^{ \infty} \frac{1}{(3n-2)(3n+1)}[/tex] I simplified it to partial fractions to (1/3) / (3n-2) - (1/3) / (3n+1) Now what?
[tex]\Sigma_{n=1}^{ \infty} \frac{1}{(3n-2)(3n+1)}[/tex] I simplified it to partial fractions to (1/3) / (3n-2) - (1/3) / (3n+1) Now what?
Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 Apr 29, 2009 #2 An infinite number of terms cancel and a finite number of terms don't. Figure out which ones don't. Start writing out terms in the partial fraction expansion for n=1,2,3,4,5... if you need to. You should see the pattern pretty quickly.
An infinite number of terms cancel and a finite number of terms don't. Figure out which ones don't. Start writing out terms in the partial fraction expansion for n=1,2,3,4,5... if you need to. You should see the pattern pretty quickly.