ciubba
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I need to find the local extrema of
\pi r^2(\frac{16}{(r+.5)^2}-1)
which I derived and simplified to
\frac{16 \pi r}{(r+.5)^3}=2 \pi r
which simplifies to \frac {16 \pi r}{2 \pi r}=(r+.5)^3
The radius cannot be zero, so I simplified 8=(r+.5)^3
I used the binomial theorem and more algebra to obtain
r^3+1.5r^2+.75r-7.875
Now I am unsure of how to simplify the cubic. Normally I would use rational roots, but I don't know how to do that with an integer constant. I need either a method of simplifying this cubic or a place where I could have simplified the derivative better.
\pi r^2(\frac{16}{(r+.5)^2}-1)
which I derived and simplified to
\frac{16 \pi r}{(r+.5)^3}=2 \pi r
which simplifies to \frac {16 \pi r}{2 \pi r}=(r+.5)^3
The radius cannot be zero, so I simplified 8=(r+.5)^3
I used the binomial theorem and more algebra to obtain
r^3+1.5r^2+.75r-7.875
Now I am unsure of how to simplify the cubic. Normally I would use rational roots, but I don't know how to do that with an integer constant. I need either a method of simplifying this cubic or a place where I could have simplified the derivative better.