- #1
ritwik06
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Homework Statement
Prove
[tex]\frac{sin 2 \alpha}{1+cos 2 \alpha}-\frac{cos \alpha}{1+cos \alpha}=tan \frac{ \alpha}{2}[/tex]
Use half and double angle formulas, I get;
The given expression is equal to:
[tex]\frac{(2 tan \frac{\alpha}{2})(1+tan^{2} \frac{\alpha}{2})}{1-tan^{2}\frac{\alpha}{2}}+2 tan \frac{\alpha}{2}+tan^{2}\frac{\alpha}{2}-1[/tex]
Please help me simplify this to only [tex]tan \frac{\alpha}{2}[/tex]
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