Sin 0?

1. Aug 7, 2014

niknak98

Teacher assigned this on first day due tomorrow and i have no clue on some like this one:

Sin 0=Ry/Rx a.) solve for Ry
b.) solve for Rx
c.) solve for 0

????

2. Aug 7, 2014

Student100

Is there anymore information you can provide? Is that actually Sin(0)? Did you attempt to solve it on your own? Have you tried the inverse function?

Anyway, if it really is 0 then it should be obvious. Ry would have to be zero. Rx is then any real which is not equal to zero. Rewriting the equation as arcsin(Ry/Rx) = 0 will demonstrate this as well. I'm saying this because part of me doesn't believe that is really supposed to be sin(0), instead it's probably theta.

Last edited: Aug 7, 2014
3. Aug 7, 2014

HallsofIvy

I can make absolutely no sense out of "solve for 0"! That would be like saying "solve for 2".

I strongly suspect that was supposed to be $sin(\theta)= R_y/R_x$ and your teacher (or you!) missed the horizontal line on the $\theta$.

To "solve for y", multiply both sides by $R_x$. To "solve for x" one method is to first invert both sides, getting $1/sin(\theta)= R_x/R_y$ and then multiply both sides by $R_y$. To "solve for $\theta$" take the inverse sin (arcos or $sin^{-1}$) of both sides.

4. Aug 9, 2014

niknak98

Thanks this really helped and he did correct it that the 0 was theta