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Sin 0?

  1. Aug 7, 2014 #1
    Teacher assigned this on first day due tomorrow and i have no clue on some like this one:

    Sin 0=Ry/Rx a.) solve for Ry
    b.) solve for Rx
    c.) solve for 0

    ????
     
  2. jcsd
  3. Aug 7, 2014 #2

    Student100

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    Is there anymore information you can provide? Is that actually Sin(0)? Did you attempt to solve it on your own? Have you tried the inverse function?

    Anyway, if it really is 0 then it should be obvious. Ry would have to be zero. Rx is then any real which is not equal to zero. Rewriting the equation as arcsin(Ry/Rx) = 0 will demonstrate this as well. I'm saying this because part of me doesn't believe that is really supposed to be sin(0), instead it's probably theta.
     
    Last edited: Aug 7, 2014
  4. Aug 7, 2014 #3

    HallsofIvy

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    I can make absolutely no sense out of "solve for 0"! That would be like saying "solve for 2".

    I strongly suspect that was supposed to be [itex]sin(\theta)= R_y/R_x[/itex] and your teacher (or you!) missed the horizontal line on the [itex]\theta[/itex].

    To "solve for y", multiply both sides by [itex]R_x[/itex]. To "solve for x" one method is to first invert both sides, getting [itex]1/sin(\theta)= R_x/R_y[/itex] and then multiply both sides by [itex]R_y[/itex]. To "solve for [itex]\theta[/itex]" take the inverse sin (arcos or [itex]sin^{-1}[/itex]) of both sides.
     
  5. Aug 9, 2014 #4
    Thanks this really helped and he did correct it that the 0 was theta
     
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