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Here's how i did it and its probably wrong so i need help:

V

_{i}= 0

θ = 45°

V

_{f}= ?

0.5mv

^{2}= mgh

v = √(2gh)

v = √(19.6*4)

V

_{f}= 8.85 m/s

V

_{y}= 8.85sin45 = 6.26 m/s = V

_{x}

D

_{y}= V

_{y}t - 0.5at

^{2}

0 = 6.26t - 4.9t

^{2}

t = 1.28s

D = V

_{x}t

D = (6.26)(1.28) = 11 m

Therefore the answer is (11 - 5) 6 m which is the distance the ball travelled beyond the fence.

It looks correct except for the height which I don't know if picking 4 was the right idea and would screw up my entire answer, so please someone help.