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Sin/Cos In Equation

  1. Jan 1, 2012 #1
    1. Trying to understand how to work a given angle into an answer in projectile motion problems.

    2. ΔX=ViTf+1/2ATf^2
    R=2vi^2sinθcosθ/g

    3. Well, I know if you're given say 45° then you would use sin for vertical and cos for horizontal. But beyond that, what are you supposed to do with an angle when given one.

    ALSO:
    For the first equation, do you substitute Vi for Visinθ or Vicosθ?
     
  2. jcsd
  3. Jan 1, 2012 #2

    SammyS

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    It depends upon how θ is defined ! (Answer to both questions)
     
  4. Jan 1, 2012 #3
    Can you explain a little more on that?
     
  5. Jan 2, 2012 #4

    SammyS

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    Sure.
     
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