Solving Equations Using Sin/Cos: Projectile Motion

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When given an angle in projectile motion problems, you would use the sine and cosine functions to determine the vertical and horizontal components of velocity, respectively. This can then be substituted into the equations for displacement and range to solve for the unknown variables. However, the specific value of θ depends on how it is defined in the problem.
  • #1
Let It Be
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1. Trying to understand how to work a given angle into an answer in projectile motion problems.

2. ΔX=ViTf+1/2ATf^2
R=2vi^2sinθcosθ/g

3. Well, I know if you're given say 45° then you would use sin for vertical and cos for horizontal. But beyond that, what are you supposed to do with an angle when given one.

ALSO:
For the first equation, do you substitute Vi for Visinθ or Vicosθ?
 
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  • #2
It depends upon how θ is defined ! (Answer to both questions)
 
  • #3
SammyS said:
It depends upon how θ is defined ! (Answer to both questions)

Can you explain a little more on that?
 
  • #4
Let It Be said:
Can you explain a little more on that?

Sure.
 
  • #5


I would like to provide some clarification and explanation on how to solve projectile motion problems using sin and cos. Projectile motion is a type of motion in which an object is thrown or launched into the air and then moves under the influence of gravity. In order to solve these types of problems, we use equations that involve the trigonometric functions sine and cosine.

In the first equation provided, ΔX represents the displacement or distance traveled in the horizontal direction, Vi is the initial velocity, Tf is the final time, A is the acceleration due to gravity, and g is the gravitational constant. In this equation, we do not substitute Vi for Visinθ or Vicosθ. Instead, we use the value of Vi as it is given in the problem. The angle θ is used in the second equation provided, which calculates the range or horizontal distance traveled by the object. In this equation, we use both sine and cosine since we are taking into account both the vertical and horizontal components of the initial velocity.

When given an angle in a projectile motion problem, it is important to remember that this angle represents the angle at which the object is launched or thrown. This angle is measured from the horizontal axis. In order to solve the problem, we need to break down this angle into its vertical and horizontal components using sine and cosine. For example, if we are given an angle of 30°, we can use sin30° to calculate the vertical component and cos30° to calculate the horizontal component.

In summary, when solving projectile motion problems, we use trigonometric functions such as sine and cosine to break down the initial velocity into its vertical and horizontal components. These components are then used in the equations to calculate the displacement and range of the object. It is important to carefully consider the given angle and use the appropriate trigonometric function for each component.
 

1. How do you solve equations using sin/cos for projectile motion?

To solve equations using sin/cos for projectile motion, you first need to identify the initial velocity, angle of projection, and height of the object. Then, you can use the equations of motion (using sin/cos) to calculate the horizontal and vertical components of the object's position and velocity at different time intervals.

2. What is the significance of using sin/cos in solving projectile motion equations?

Sin/cos are trigonometric functions that relate the angles and sides of a right triangle. In projectile motion, the angle of projection and the height of the object can be represented using these functions, making it easier to calculate the horizontal and vertical components of the object's motion.

3. Can you explain how to find the maximum height and range of a projectile using sin/cos?

To find the maximum height of a projectile, you can use the equation h = u*sin(theta)^2/2g, where h is the maximum height, u is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity. To find the range, you can use the equation R = u^2*sin(2*theta)/g.

4. Are there any limitations to using sin/cos in solving projectile motion equations?

One limitation is that it assumes a perfectly flat and uniform surface for the projectile to travel on. In reality, there could be air resistance, uneven terrain, or other factors that can affect the motion of the object. Additionally, these equations do not take into account external forces acting on the object, such as wind or air resistance.

5. Can you provide an example of solving a projectile motion equation using sin/cos?

Sure, let's say an object is launched with an initial velocity of 20 m/s at an angle of 45 degrees above the horizontal. Using the equations h = u*sin(theta)^2/2g and R = u^2*sin(2*theta)/g, we can calculate that the maximum height of the object is 10 meters and the range is approximately 40 meters.

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