Sine Graph Help: Calculating Uoutput & Drawing Graph

  • Thread starter Thread starter the_man
  • Start date Start date
  • Tags Tags
    Graph Sine
AI Thread Summary
The discussion revolves around calculating the output of an inverting op-amp given an input sine graph. The user is uncertain about the horizontal shift of the output signal, questioning whether it should be +120° or -60°. They believe their calculated output function, Uout = 1.43*sin(104.7*10^3*t + 120), is correct and are confused by conflicting information from a friend and Google. The user is encouraged to plot the output to verify its resemblance to the inverted input. The main focus is on understanding the correct phase shift for the output signal in relation to the input.
the_man
Messages
14
Reaction score
0

Homework Statement



TASK

So I have this task with opamp and I have Uinput Sine Graph, now I have to calculate Uoutput and write it as sine function and draw the sine graph. I know that this is an inverting OPAMP which means that output signal will be inverted, so I just have to flip this Input signal, right? With input signal the horizontal shift is -60° and when I invert the signal it will be +120°, right? This is the problem, I know how to calculate everything, but I am not sure about horzontal shift of output signal, because my friend is keep telling me its -60, and also more important Google is telling that

Now my solution is Uout = 1.43*sin(104,7*10^3*t + 120)

https://www.google.hr/#q=1.43*sin(0.53*t+-+60)
https://www.google.hr/#q=1.43*sin(0.5*t+++120)

Homework Equations



Are google and my friend wrong? Or am I wrong?

The Attempt at a Solution



My Solution
 
Physics news on Phys.org
1.43*sin(104,7*10^3*t + 120)

You think this is the answer, so why don't you plot this on graph paper and see whether it resembles the input inverted?
 
I think I am right. Take a look at google link for where solution is +120°. Why is google moving that graaph 120°? It should be moved 120° left of y-axis, right?
 
Back
Top