Sine Graph Help: Calculating Uoutput & Drawing Graph

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SUMMARY

The discussion centers on calculating the output of an inverting operational amplifier (op-amp) given an input sine wave. The user has derived the output function as Uout = 1.43*sin(104.7*10^3*t + 120°) and seeks clarification on the horizontal shift of the output signal. The confusion arises from differing opinions on the phase shift, with the user asserting that the output should be shifted +120°, while a friend claims it should be -60°. The consensus is that the output phase shift for an inverting op-amp is indeed +120°.

PREREQUISITES
  • Understanding of inverting operational amplifier (op-amp) configurations
  • Knowledge of sine wave functions and phase shifts
  • Familiarity with trigonometric transformations in signal processing
  • Ability to plot sine functions on graph paper or using graphing software
NEXT STEPS
  • Study the principles of inverting op-amps in detail
  • Learn how to calculate phase shifts in AC circuits
  • Explore graphing techniques for sine functions using tools like Desmos or MATLAB
  • Review signal processing concepts related to amplitude and phase modulation
USEFUL FOR

Students studying electrical engineering, particularly those focusing on circuit analysis and signal processing, as well as anyone working with operational amplifiers and sine wave functions.

the_man
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Homework Statement



TASK

So I have this task with opamp and I have Uinput Sine Graph, now I have to calculate Uoutput and write it as sine function and draw the sine graph. I know that this is an inverting OPAMP which means that output signal will be inverted, so I just have to flip this Input signal, right? With input signal the horizontal shift is -60° and when I invert the signal it will be +120°, right? This is the problem, I know how to calculate everything, but I am not sure about horzontal shift of output signal, because my friend is keep telling me its -60, and also more important Google is telling that

Now my solution is Uout = 1.43*sin(104,7*10^3*t + 120)

https://www.google.hr/#q=1.43*sin(0.53*t+-+60)
https://www.google.hr/#q=1.43*sin(0.5*t+++120)

Homework Equations



Are google and my friend wrong? Or am I wrong?

The Attempt at a Solution



My Solution
 
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1.43*sin(104,7*10^3*t + 120)

You think this is the answer, so why don't you plot this on graph paper and see whether it resembles the input inverted?
 
I think I am right. Take a look at google link for where solution is +120°. Why is google moving that graaph 120°? It should be moved 120° left of y-axis, right?
 

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