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Hi PF!
Let's say we have a matrix that looks like $$
A = \begin{bmatrix}
1-x & 1+x \\
i & 1
\end{bmatrix} \implies\\ \det(A) = (1-x) -i(1+x).
$$
I want ##A## to be singular, so ##\det(A) = 0##. Is this impossible?
Let's say we have a matrix that looks like $$
A = \begin{bmatrix}
1-x & 1+x \\
i & 1
\end{bmatrix} \implies\\ \det(A) = (1-x) -i(1+x).
$$
I want ##A## to be singular, so ##\det(A) = 0##. Is this impossible?