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Sinusoidal sources and complex power

  1. Nov 30, 2012 #1
    When calculating power in a given circuit, why is the complex conjugate of the current used to compute power?
     
  2. jcsd
  3. Nov 30, 2012 #2
    darbitman,

    You mean apparent power, don't you?

    Easy, the apparent power is I^2 multiplied by Z, which equals I* times I times Z, which equals I* times V. I* is the conjugate of I, I^2 = I times I*, and I times Z = V .

    Ratch
     
  4. Nov 30, 2012 #3
    I meant apparent power, sorry. And thank you for the explanation.
     
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