SinX is defined for any angles [0,∞) ?

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The sine function, sin(x), is defined for all real numbers, including both positive and negative angles, contrary to the claim that it is only defined for [0,∞). The discussion highlights that the sine function is an odd function, meaning sin(-x) = -sin(x), which does not restrict its definition to positive angles only. The textbook's assertion that sin(x) is only defined for angles in the range [0,∞) is incorrect; it is actually defined for all angles, including negative ones. Additionally, the sine function can yield negative values for certain positive angles, further emphasizing its comprehensive domain. Overall, the sine function's definition encompasses all real numbers, including complex numbers.
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SinX is defined for any angles [0,∞) ?

Homework Statement



SinX is defined for any angles [0,∞)

Homework Equations



Ok, the domain of sinX is -∞< x < ∞

The Attempt at a Solution



Someone said "You are confused due to fact that Sin(-x)= - sin(x)." Does it mean that just because sinX is not exactly -sinX, sinX will be undefined for all the negative angles since they will produce negative sine function values and we are only interested in positive sine function?

Thanks.
 
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solve said:

Homework Statement



SinX is defined for any angles [0,∞)
Are you referring to the restricted sine function, "Sin x"? If so, the domain of Sin x isn't [0,∞), but [-π/2, π/2].
 


eumyang said:
Are you referring to the restricted sine function, "Sin x"? If so, the domain of Sin x isn't [0,∞), but [-π/2, π/2].

This is from my textbook:

Start with the circle generated by the endpoint A of a straight line OA of unit length rotating anticlockwise about the end O. For angles X where 0<x<pi/2 radians you already know that sinX=AB/AO=AB since AO=1.

That is, the value of the trig ratio sinX is equal to the height of A above B. The sine function with output sinX is now defined as the height of A above B for any angle X (0≤x<∞)
 


To me it just looks like your textbook is wrong... The sine function is certainly defined for negative angles too (as well as complex numbers, if you know what those are...)

Your statement in 3. makes no sense, since the sine function takes on negative values for some positive x too. But anyway, there are no such restrictions on functions in general, the so-called odd functions (like sin(x)) and even functions (like cos(x)) are special cases. Also, if sin(x) = - sin(x), then sin(x) = 0 ...
 


niklaus said:
To me it just looks like your textbook is wrong... The sine function is certainly defined for negative angles too (as well as complex numbers, if you know what those are...)

Your statement in 3. makes no sense, since the sine function takes on negative values for some positive x too. But anyway, there are no such restrictions on functions in general, the so-called odd functions (like sin(x)) and even functions (like cos(x)) are special cases.

Indeed, sin((3 * pi) / 2) = -1. Weird.

niklaus said:
Also, if sin(x) = - sin(x), then sin(x) = 0 ...

I have to think about how this ties with the rest.
 


It doesn't. If A= -A, then, adding A to both sides, 2A= 0 so, dividing both sides by 2, A= 0. That has nothing to do with trig functions.
 
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