1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Sketch the function:?

  1. Sep 19, 2009 #1
    Sketch the function:????

    Hello everyone, I was asked the following question:
    On the same axes, sketch the functions:
    f(x) = 10+3x-x^2
    g(x) = 3x^2-6x-5

    Calculate the coordinates of the two points where the two lines cross. How far apart are the two points:

    I don't even know how to start?
    Am I supposed to use the quadratic formula and first sketch f(x) and then use the quadratic formula again to sketch g(x) on the same graph??

    Please help.......
     
  2. jcsd
  3. Sep 19, 2009 #2
    Re: Sketch the function:????

    You need to find where f(x) = g(x); those will be parts of the points where the two functions intersect. Set the functions equal to each other and solve for x. You should get two x values, one for each point. Plug them into either f(x) or g(x) and then you will get the y coordinates for the two points.

    Lastly, do you know the distance formula for two points?
     
  4. Sep 19, 2009 #3

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Re: Sketch the function:????

    What do you mean by " the quadratic formula and first sketch f(x) and then use the quadratic formula again to sketch g(x) on the same graph"? How does the quadratic formula help sketch a graph, except by finding the x-intrecepts. I recommend completing the square. After you [itex]f(x)= a(x- b)^2+ c[/itex] you can easily find the x- intercepts ([itex](x- b)^2= -c/a[/itex] so [itex]x= b\pm \sqrt{-c/a}[/itex], the y-intercept ([itex]ab^2+ c[/itex]) and, perhaps most importantly, the vertex [itex](b, c)[/itex]. With those points, it should be easy to sketch the graph.
     
  5. Sep 19, 2009 #4
    Re: Sketch the function:????

    Thank you for replying.
    I followed your advised and here is what I got:
    f(x)=g(x)
    10+3x-x^2=3x^2-6x-5
    10+3x-x^2-3x^2=3x^2-3x^2-6x-5
    10+3x-4x^2= -6x-5
    10+3x-4x^2+6x=-6x+6x-5
    -4x^2+3x+6x+10=-5
    -4x^2+9x+10=-5
    -4x^2+9x+10+5=-5+5
    -4x^2+9x+15 =0

    Applied the quadratic formula and got:
    x =-1.1145
    x=3.3645

    Now,you told me to plug the two x values above to either f(x) or g(x), I don't know if you want me to do this:
    f(x) =10+3x-x^2
    f(x) =10+3(-1.1145)-(-1.1145)^2

    or this:
    f(x) =10+3x-x^2
    f(x) =10+3(-1.1145)-(3.3645)^2

    Help???????????????????
     
  6. Sep 19, 2009 #5
    Re: Sketch the function:????

    For the equation -4x2 + 9x + 15 = 0
    use the quadratic formula to to get the exact answers for x with square roots and no rounding. Let's call them x1 and x2.

    You chose f(x), so you want to first evaluate f(x1). That means plugging in only x1 in the function, as you did in the first one where you weren't sure, and not two different values as in the second one. The coordinates of that point of intersection will be (x1, f(x1)). Do the same thing with x2.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Sketch the function:?
Loading...