Sketch the graph of the function f(x)=square root X

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Discussion Overview

The discussion revolves around sketching the graph of the function f(x) = √x and its inverse functions, including y = f^-1(x) and y = -f^-1(-x). Participants explore the relationships between these functions and clarify their understanding of graph transformations and reflections.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents a chart for f(x) = √x, providing values for x and corresponding y values, but expresses uncertainty about its correctness.
  • Another participant explains that the graph of the inverse function is a reflection of the original function about the line y = x, suggesting that values of x and y should be exchanged in the tables.
  • There is a correction regarding the values for y = f^-1(x), where one participant indicates that the values provided were incorrect and emphasizes the need to swap x and y values to find the inverse function.
  • Participants discuss the reflection of the graph y = -f^-1(-x) and question the equation of the reflection line, with one participant seeking clarification on the problem statement.
  • One participant acknowledges a mistake in copying the problem and revises their values for y = f^-1(x) and y = f^-1(-x), but another participant points out that the negative sign in front of f^-1 was omitted in their revision.
  • There is a consensus that the negative sign should be included, leading to a discussion about the implications for the y values in the table.

Areas of Agreement / Disagreement

Participants express uncertainty and confusion about the correct values for the inverse functions and the reflection line. There is no clear consensus on the final representations of the functions or the reflection line equation.

Contextual Notes

Participants' discussions reveal limitations in their understanding of inverse functions and reflections, with some confusion about the correct transformations and the implications of negative signs in the equations.

Aka
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a) sketch the graph of the function f(x)=square root X
b) on the same set of axes, graph y=f^-1(x), y=-f^-1(-x)

so I did a chart, but i don't know if its right...I don't think its right :confused:

f(x)=squareroot x

X Y
0 0
1 1
4 2
9 3

y=f^-1(x)

X Y
0 0
1 -1
4 -2
9 -3

y=-f^-1(-x)

X Y
0 0
-1 1
-4 2
-9 3

and i don't understand the question
if the two graph of y=-f^-1(-x) is drawn from the graph of y=f(x) by a single reflection, what is the equation of the reflection line?

Thanks
 
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The graph of the inverse function will be the reflection of the function about the line y = x which amounts to exchanging the values of x and y in your tables and adjusting accordingly for the negative of the inverse.
 
Aka said:
a) sketch the graph of the function f(x)=square root X
b) on the same set of axes, graph y=f^-1(x), y=-f^-1(-x)

so I did a chart, but i don't know if its right...I don't think its right :confused:

f(x)=squareroot x

X Y
0 0
1 1
4 2
9 3
Yes, this is correct.

y=f^-1(x)

X Y
0 0
1 -1
4 -2
9 -3
No, this is y= -f(x), not y= f-1(x), the inverse function.
To get the inverse function, just swap the x and y columns.
What is the "opposite" of square root?

[/quote]y=-f^-1(-x)

X Y
0 0
-1 1
-4 2
-9 3 [/quote]
see above.

and i don't understand the question
if the two graph of y=-f^-1(-x) is drawn from the graph of y=f(x) by a single reflection, what is the equation of the reflection line?

Thanks
I don't understand "the two graph". Are you sure that you have copied the problem correctly? Draw the graphs as you were told two. Is there some line so that "flipping" the first graph over that line gives the second graph?
 
^ Thanks
Are you sure that you have copied the problem correctly?

sorry, I did not coppy it corrently, it's not supposed to have the two in it :P

so is it like this?

y=f^-1(x)
X Y
0 0
1 1
2 4
3 9

y=f^-1(-x)
X Y
0 0
-1 1
-2 4
-3 9
 
Aka said:
^ Thanks


sorry, I did not coppy it corrently, it's not supposed to have the two in it :P

so is it like this?

y=f^-1(x)
X Y
0 0
1 1
2 4
3 9

y=f^-1(-x)
X Y
0 0
-1 1
-2 4
-3 9

Yes, that's better. But, I believe you forgot the negative in front of the f^-1 in the second equation. Shouldn't that be y = -f^-1(-x)?
 
^ yes, it should

so the y values will be negative
 

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