Sketching Nyquist Plots for Complex Arguments

  • Thread starter Thread starter ajtgraves
  • Start date Start date
  • Tags Tags
    Complex
AI Thread Summary
The discussion centers on sketching the Nyquist plot for the function (jω - 1)/(jω + 1) and the challenges in calculating its argument. The initial calculation of the argument as -2arctan(ω) is questioned due to its implications for behavior as ω approaches 0 and infinity. A correction is suggested, noting that when the real part is negative, the argument should be adjusted by adding 180 degrees to the arctan result. This adjustment clarifies the misunderstanding and aligns the calculations with expected Nyquist plot behavior. The conversation concludes with appreciation for the clarification provided.
ajtgraves
Messages
7
Reaction score
0
I'm trying to sketch the nyquist plot of
$$\frac{j\omega-1}{j\omega+1}$$
but can't seem to calculate the argument correctly. I think it should be $$\arctan(-\omega) - \arctan(\omega) = -2\arctan(\omega)$$ but this doesn't give the correct nyquist plot behaviour for $\omega \to 0$ and $\omega \to \infty$ - surely $-2\arctan(\omega)$ implies that $\lim_{x\to 0} = 0^\circ$ and $\lim_{x\to \infty} = -180^\circ$?

Wolfram Alpha disagrees but I can't see where I'm going wrong. Am I making a glaring error somewhere? Any help would be greatly appreciated.

Thanks very much
 
Mathematics news on Phys.org
You're an electrical engineer, right? So j means the square root of -1?

Assuming it does, I think you are off by 180 degrees. The formula ##\mathrm{arg}(x + yj) = \arctan(y/x)## is valid when ##x > 0##, but if the real part of ##x + yj## is negative, as it is in the numerator, you need to adjust for the fact that arctan only returns angles in ##(-\pi/2, \pi/2)## by using ##\mathrm{arg}(x + yj) = \pi + \arctan(y/x)##.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...

Similar threads

Replies
2
Views
3K
Replies
1
Views
2K
Replies
17
Views
6K
Replies
25
Views
4K
Replies
3
Views
2K
2
Replies
67
Views
11K
Replies
2
Views
6K
Back
Top