Sketching Root Locus of System: K Varies 0 to ∞

  • Thread starter Thread starter weavertri
  • Start date Start date
  • Tags Tags
    Root Root locus
AI Thread Summary
To sketch the root locus of the system as K varies from 0 to infinity, the characteristic equation is derived as (s+2)(s+5)(s+K) + 10K = 0. This expands to s³ + 7s² + 10s + K(s² + 7s + 20) = 0. The equation can be reformulated to 1 + K(s + 3.5 - 2.8i)(s + 3.5 + 2.8i)/(s(s+2)(s+5)) = 0, identifying the zeros at z1= 3.5 + 2.8i and z2= 3.5 - 2.8i, with poles at p1=0, p2=-2, and p3=-5. This framework allows for the effective sketching of the root locus based on the identified poles and zeros.
weavertri
Messages
5
Reaction score
1
Hello guys, I need help to sketch the root locus of the system when K is varying from 0 to infinity. (K>=0)
The system:
http://www.freeimagehosting.net/newuploads/anspe.jpg

I'm stuck. I really don't know how proceed.
Thanks in advance.
 
Physics news on Phys.org
Plot the poles and zeroes (There are no zeroes here). Use the root locus drawing rules.
 
yeah, that's what I'm doing... the problem is: K is not a constant. to use the root locus drawing rules the characteristic equation of the closed loop system must be written as 1 + GH = 0. All that I got in this case is
(s+2)(s+5)(s+K) + 10K = 0.
 
I guess I finally did it.
my characteristic equation is (s+2)(s+5)(s+K) + 10K = 0.
we expand to s³ + 7s² + 10s + Ks² 7Ks + 20K = 0
the C.E. must be written as 1 + K*F(s) = 0, then

s³ + 7s² + 10s + K(s² + 7s + 20) = 0

1 + K(s² + 7s + 20)/( s³ + 7s² + 10s) = 0



this is equal to

1 + K(s + 3.5 - 2.8i)(s + 3.5 + 2.8i)/(s(s+2)(s+5)) = 0


now we can sketch the root locus where the zeros are (z1= 3.5 + 2.8i and z2 = 3.5 - 2.8i) and the poles p1=0, p2=-2 and p3=-5.

:)
 
Back
Top