Slope and deflection diagrams using conjugate beam method

AI Thread Summary
The discussion focuses on constructing slope and deflection diagrams using the conjugate beam method for a given beam problem. The original shear and moment equations are provided, and the user has drawn the conjugate beam but is uncertain about how to proceed with the shear and moment diagrams due to complex loading. Guidance is offered on using integration to find slopes and deflections, emphasizing that the slope should be zero at the fixed end and nonzero at the free end. Additionally, the importance of showing detailed work for clarity and potential partial credit during grading is highlighted. The conversation underscores the necessity of understanding integration constants and consulting statics resources for better comprehension.
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Homework Statement


Construct the slope and deflection diagrams. I've attached the problem with the original diagram (problem #1).

The Attempt at a Solution


Considering the number of diagrams required, I thought it would be best to attach a photo of my work.
I drew the shear and moment diagrams for the original beam, with equations for V and M as follows:
V = {150 (0<x<3), -75x (3<x<5)
M = {150x (0<x<3), -75/2*x2 + 375x (3<x<5)

I then drew the conjugate beam, which is essentially a mirror image of the original beam. I then loaded it with M/EI, where M is the moment from the original beam. Now, I know I need to draw the shear and moment diagrams for the conjugate beams, and these will be the slope and deflection diagrams. I'm just not sure how to go about this, considering the complicated loading.
Also, for another problem, I am told to find the max deflection. Is there a way to do this without constructing the shear and moment diagrams(for the conjugate beam)?

Thank you.
 

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Use an "integration" method, rather than a "cutting" method.

1) Get your reactions in you conjugate beam.

2) Integrate to get the slope (makes no difference if you start at the left end or the right end). You should find that you get zero at the left end of your conjugate beam, and something nonzero (equal and opposite to your reaction) at the right end of your conjugate beam. So, in the actual beam, the slope is zero at the fixed end and nonzero at the free end (as expected).

3) Integrate (2) to get the deflection.
You will find that you again get zero at the left end of your conjugate beam, and something nonzero at the right end of your conjugate beam. So, in the actual beam, the deflection is zero at the fixed end and nonzero at the free end (as expected).

Hope that helps,
 
I got RC'y=1425/EI and MC'=4387.5/EI .
I also found the equations for V and M of the conjugate beam. Do I need to consider end conditions to find integration constants? As it stands right now, my shear diagram goes down to -900/EI at x=3, and with the equation I have for 3<x<5, it would go towards the axis. However, the reaction I found at C' would need the diagram to end at -1425/EI at x=5.

Attached is more of my work.
Thank you.
 

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To answer your question regarding "integration constants" -- yes, I would expect to see some constant values in your equations. My advice would be to consult a statics textbook if you aren't familiar with the "integration" method for finding shear and moment diagrams.

Some more advice, just to help you out, because I've been in your position:
Show a lot more work.

The grader can't give you partial credit if they cannot follow your steps. For example, I have no idea how you got your equations because you don't show the steps that you took in order to arrive at them. Where are the integrals? I expected to see an integral sign "∫" somewhere in your work.
 
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