Snowball Projectile Motion Calculation: Time, Height, and Velocity

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SUMMARY

The discussion centers on calculating the projectile motion of a snowball thrown horizontally at a velocity of 18 m/s from a height of 1.5 m and a distance of 9.0 m from a tree. The time interval for the snowball to hit the tree is determined to be 0.5 seconds using the formula t = d/v. The vertical component of the snowball's initial velocity (viy) is zero due to the horizontal throw, which is crucial for calculating the height at impact and the final velocity upon striking the tree.

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Homework Statement


A child throws a snowball with a horizontal velocity of 18m/s directly toward a tree, from a distance of 9.0m and a height above the ground of 1.5m

a) after what time interval does the snowball hit the tree?
b) at what height above the ground will the snowball hit the tree?
c) determine the snowball's velocity as it strikes the tree.


Homework Equations



v=d/t

The Attempt at a Solution



For a I got 0.5s from t = d/v

For b and c I have no idea. I am missing the viy value. I have no idea how to any other information.
 
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barthayn said:

Homework Statement


A child throws a snowball with a horizontal velocity of 18m/s directly toward a tree, from a distance of 9.0m and a height above the ground of 1.5m

a) after what time interval does the snowball hit the tree?
b) at what height above the ground will the snowball hit the tree?
c) determine the snowball's velocity as it strikes the tree.


Homework Equations



v=d/t

The Attempt at a Solution



For a I got 0.5s from t = d/v
yes OK; ultimately you'll have to be sure that the snowball doesn't hit the ground before it reaches the tree.
For b and c I have no idea. I am missing the viy value. I have no idea how to any other information.
The problem statement notes that the snowball is thrown with a horizontal velocity. What does that tell you about the snowball's initial speed in the vertical y direction?
 

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