Solution for System of Equations: (-5,5)

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Discussion Overview

The discussion revolves around determining whether the point (-5, 5) is a solution to a given system of equations: 6x - 3y = -45 and x + 3y = -15. The focus is on the process of substituting the values into the equations to verify the solution.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • Participants discuss the method of substituting x = -5 and y = 5 into the first equation, 6x - 3y = -45, to check if it holds true.
  • One participant calculates the left-hand side of the first equation after substitution and finds it equals -45, indicating it satisfies the equation.
  • Participants then consider the second equation, x + 3y = -15, and substitute the same values to check for validity.
  • Another participant performs the substitution for the second equation and finds the left-hand side equals 10, which does not match the right-hand side of -15, suggesting that (-5, 5) is not a solution.

Areas of Agreement / Disagreement

Participants generally agree on the substitution method for checking the solution, but they arrive at different conclusions regarding the validity of (-5, 5) as a solution to the second equation.

Contextual Notes

The discussion does not resolve the overall question of whether (-5, 5) is a solution to the system, as the first equation is satisfied while the second is not.

Happymom
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Hi I need help with this problem

Determine if (-5,5) is a solution to the given system of equations

6x - 3y = -45
x + 3y = -15

Thanks
 
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Happymom said:
Hi I need help with this problem

Determine if (-5,5) is a solution to the given system of equations

6x - 3y = -45
x + 3y = -15

Thanks

Hi Happymom! Welcome to MHB :)

To check this, you need to "plug in" -5 for x and 5 for y. Let's try the first one.

6x - 3y = 45

6(-5)-(3)(5) is the left hand side after we plug in x and y that they gave us. If we simpligy that we get -30-15=-45, which is good because in order to be a solution the left and right hand sides must be equal at the solution point.

Can you test the second equation?
 
Hi Jameson

would x = -5 for x + 3y = -15
 
Happymom said:
Hi Jameson

would x = -5 for x + 3y = -15

Exactly! :) I forgot to mention the point (-5,5) is using the general form of (x,y). You'll see that often in graphing so it's worth memorizing. What do you get after plugging in x and y for the 2nd line?
 
Jameson

I'm stumped! Can you show thanks :confused:
 
Happymom said:
Jameson

I'm stumped! Can you show thanks :confused:

Of course. The 2nd equation we are testing is x + 3y = -15. We are testing (-5,5) or x=-5 and y=5. Now we just replace any x's we see with -5 and any y's with 5.

That gives us -5+3(5) for the left hand side. That simplifies to -5+15=10. Uh oh! The right hand side of the original equation was -15 and we found the left hand side is 10 at this point so it's not a solution. Whenever a solution is valid you'll end up with something like 10 = 10 or -22 = -22 after testing the solution with your equation. Those are both true statements so that would mean the solution is valid.

In our problem just now, we found a result that wasn't true since 10 does not equal -15.
 

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