Proving G is Solvable or Finding a Counter-Example

  • Thread starter Thread starter burritoloco
  • Start date Start date
burritoloco
Messages
81
Reaction score
0

Homework Statement


Suppose G has a solvable maximal normal subgroup. Either prove G is solvable, or give a counter-example.


Homework Equations





The Attempt at a Solution


We have that G/H is simple, not necessarily abelian, so my guess is there could be a counter-example. However, I'm not sure what it is.
I know the symmetric group S_5 is not solvable and it has the unique proper normal subgroup A_5, but A_5 is not solvable, so this doesn't work as a counter.
Moreover, the quaternion group, dihedral groups are solvable too. Any help please?
My exam is tomorrow... Thanks for the help!
 
Physics news on Phys.org
What if G is the direct product of a solvable group with something suitable? Can this give you a counterexample?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top