Solve 2D Motion Problem: Initial Velocity 8.40m/s, Angle 17°

AI Thread Summary
The discussion revolves around solving a 2D motion problem involving a ball thrown from a building with an initial velocity of 8.40 m/s at a 17° angle below the horizontal. Participants clarify that the angle below the horizontal does not imply a negative value but affects the calculations for horizontal and vertical components. The key to solving the problem is to separate the motion into horizontal and vertical components using trigonometric functions. Hints are provided for calculating horizontal distance, height, and the time taken to reach a specific vertical point. Understanding the breakdown of projectile motion is essential for finding the correct answers.
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Homework Statement


A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8.40m/s at an angle of 17° below the horizontal. It stikes the ground 4.00 s later.

a. How far horizontally from the base of the building does the ball strike the ground?
b. Find the height from which the ball was thrown
c. How long does it take the ball to reach a point 10.0 m below the level of launching?

Homework Equations





The Attempt at a Solution



I don't understand how it can be 17° below the horizonal axis. If it is below the x axis, doesn't that mean that it is negative? Would I just use cos and sin for parts a and b? Could someone please give me a hint on part c?

Thank you very much
 
Physics news on Phys.org
It's not impossible to throw a ball downwards from a building. You have a velocity, time, and you have the angle to the horizontal. Remember, break projectile motion problems into x and y situations.
 
Thank you very much

Regards
 

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