Solve 3log25 - log34 + log2(log39): 6.335

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The discussion centers on solving the expression 3log25 - log34 + log2(log39) and identifying errors in the calculations. The initial attempt yielded an answer of approximately 6.7039, which is incorrect compared to the expected result of 6.335. A participant points out a typo in the logarithmic transformation, clarifying that log2(log39) should be interpreted correctly. Despite confirming the steps taken in the calculations, the correct resolution of the equation remains elusive. The conversation highlights the complexity of logarithmic functions and the importance of precise notation in mathematical expressions.
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This question should be easy to most people here and need some help on this question.

3log25 - log34 + log2(log39)

My answer to this question is:
= 3log25 - log34 + log2(log9/log3)
= log2125 - log34 + log22
= log2125 - log34 + 1
= (log125 / log2) - (log4 / log3) + 1
= 6.703924778

However the correct answer give is 6.335, which means my answer is wrong. Can somebody tell me what's wrong with my answer and what should I do to get the correct answer? :frown:

Thanks :)
 
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These steps you have made do not make any sense:

\log_2 \log_2 9 \Rightarrow \log_2 \left( \frac{\log 9}{\log 3} \right) \Rightarrow \log_2 2
 
opps...sorry. i had a typo in my post. edited it

it should be:
\log_2 \log_3 9 \Rightarrow \log_2 \left( \frac{\log 9}{\log 3} \right) \Rightarrow \log_2 2

but i still cannot solve this equation. :(
 
Well in that case your reduction of the logs is perfectly correct and your approximation to the number in decimal places is also correct. The number is about:

6.7039247775191721694119040597826488189953228988...
 
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