Solve Ali's Solid Volume Puzzle: 9 Faces, 27 cm^3 Cubes

AI Thread Summary
Ali's solid volume puzzle involves creating a solid from cubes, each with a volume of 27 cm^3. The goal is to determine the smallest volume of a solid with 9 faces, given that Ali previously created a solid with 10 faces and a volume of 108 cm^3. Participants in the discussion explore various combinations of cubes, noting that using four cubes yields face counts of 5, 8, 10, 13, 15, and 20. There is uncertainty about whether the puzzle restricts the number of cubes used, with some suggesting that using more cubes may allow for achieving the desired face count. The conversation emphasizes the need for experimentation with cube arrangements to find a viable solution.
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Homework Statement



Ali is making solids out of cubes . Each cube has a volume of 27 cm^3. The diagram shows one solid Ali made . It has 10 faces and a volume of 108 cm^3. Ali made a solid out of the cubes that has 9 faces.What is the smallest volume in cm^3 the solid could have?

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The Attempt at a Solution

 

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Have you done any calculations yet? What's your attempt at this so far? :smile:
 
Axiom17 said:
Have you done any calculations yet? What's your attempt at this so far? :smile:

I tried rearranging those cubes to get a solid with 9 faces. Any hints?
 
Good start :smile: I've tried that approach too, but.. is it even possible?! :rolleyes:

I can only seem to be able to get either 6, 8, or 10 sides, when arranging those 4 cubes, and I'm sure I've tried all possible combinations as I suppose you have done already as well.

The question seemed to imply that only those 4 cubes were used, but not sure if maybe then you can use as many as you like. Would certainly seem to be more possible then.
 
I think the question asks for as many cubes as you like.

Start with
1 cube: 5 faces;
2 cubes: 5 faces, 10 faces;
3 cubes: 5 faces, 8 faces, 10 faces, 15 faces;
4 cubes: 5 faces, 8 faces, 10 faces, 13 faces, 15 faces, 20 faces;

Now you try, and give me the answer.
 
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.. I see a pattern! :wink:
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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