Solve Ampere's Law Problem for Uniform Current Density

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To solve the Ampere's Law problem for a conducting slab with uniform current density, the integral form of Ampere's Law is applied: the integral of the magnetic field B over a closed path equals μ₀ times the enclosed current density. The challenge arises from the lack of cylindrical symmetry, leading to confusion about the appropriate integration path. A rectangular loop is suggested for the integration, with its legs oriented either parallel or perpendicular to the magnetic field. This approach simplifies the calculation of the magnetic field in the region surrounding the slab. The discussion emphasizes the need to adapt standard methods to non-cylindrical geometries when applying Ampere's Law.
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Homework Statement


A conducting slab of thickness a is bounded by the planes z= \pma/2 and carries a uniform current density J=J (y hat)

Use the integral form of Ampere's law to to find magnetic field everywhere
2. Relevant equations

Integral for of Amperes law: Integral (B \bullet ds) = \mu 0 Jenclosed

The Attempt at a Solution



All of the examples in class and in the book use cylindrical symmetry so I was a bit perplexed as how to approach taking an integral over a closed path dotted into a B in cylindrical coordinates.
 
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Try using a rectangular loop for the integration. Each leg of the loop is either perpendicular or parallel to B.
 
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