Solve Angular Acceleration for Blade Radius | Homework Help

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A fan blade is rotating with a constant angular acceleration of +12.0 rad/s², and the problem is to find the radius at which tangential acceleration equals gravitational acceleration (9.80 m/s²). The equation used is aT = rα, rearranged to r = aT/α, leading to r = 0.0817 m/rad, which is incorrect. The correct answer is 0.817 m, highlighting a misunderstanding of units, as radians are dimensionless and do not affect the dimensional analysis. The discussion clarifies that while radians are used in calculations, they do not contribute to the final unit of measurement for radius.
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Homework Statement



A fan blade is rotating with a constant angular acceleration of +12.0 rad/s2. At what point on the blade, as measured from the axis of rotation, does the magnitude of the tangential acceleration equal that of the acceleration due to gravity?

Homework Equations



aT=(r)(\alpha)

The Attempt at a Solution



What I did is rearrange the equation so that r=aT/\alpha
This gave me r=(9.80m/s^2)/(12.0rad/s^2)
So, r=0.0817 m/rad

The answer is supposed to be 0.817 m, but why am I getting m/rad? In fact, m/rad doesn't even make sense. Is there another way to rearrange the equation?

Any help is much appreciated. Thank you.
 
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Radians, although a unit of measure, are dimensionless. You are getting the correct answer using a correct method.

A similar situation is in the arc length of a circle. s = rθ has the same issue where s is the arc length (meters), r is the radius (meters) and θ is the subtended angle (radians). In a circle, θ is defined by this formula as being the arc length divided by the radius. Being two distance measurements, the units cancel to be dimensionless.

We use the term radians to differentiate it from other angle measurements like degrees which are measured as being the ratio s/r = 1/360.

While looking up information that would help explain this, I found a similar question someone asked.

I suggest reading it to further your understanding of angle measurements: http://mathforum.org/library/drmath/view/64034.html
 
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